What are the solutions to the equation k^2-4k+69=-3 ?

The solutions to the equation k^2-4k+69=-3 are k=2+2sqrt(17)i,k=2-2sqrt(17)i

Find the zeros of k^2-4k+69=-3

The zeros of k^2-4k+69=-3 are k=2+2sqrt(17)i,k=2-2sqrt(17)i

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k^{2} - 4 k + 69 = - 3

k = 2 + 217 i, k = 2 - 217 i

Solution steps

k^{2} - 4 k + 69 = - 3

Move

3

to the left side

k^{2} - 4 k + 72 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 72}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot 72 : 417 i

k_{1, 2} = \frac{- ( - 4 ) \pm 4 17 i}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- ( - 4 ) + 4 17 i}{2 \cdot 1}, k_{2} = \frac{- ( - 4 ) - 4 17 i}{2 \cdot 1}

k = \frac{- ( - 4 ) + 4 17 i}{2 \cdot 1} : 2 + 217 i

k = \frac{- ( - 4 ) - 4 17 i}{2 \cdot 1} : 2 - 217 i

The solutions to the quadratic equation are:

k = 2 + 217 i, k = 2 - 217 i

x^{2} - 25 = 12, x + 5 = 4, x - 5

x^{2} - 10 x + 25 = - 16 + 25

\frac{- 1}{6} x^{2} + x - 3 = 0

- 21 x^{2} + 31 x + 26 = 0

6 x^{2} + 240 = 0

What are the solutions to the equation k^2-4k+69=-3 ?
The solutions to the equation k^2-4k+69=-3 are k=2+2sqrt(17)i,k=2-2sqrt(17)i
Find the zeros of k^2-4k+69=-3
The zeros of k^2-4k+69=-3 are k=2+2sqrt(17)i,k=2-2sqrt(17)i