What are the solutions to the equation s^2+10s+25=0 ?

The solutions to the equation s^2+10s+25=0 are s=-5

Find the zeros of s^2+10s+25=0

The zeros of s^2+10s+25=0 are s=-5

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s^{2} + 10 s + 25 = 0

s = - 5

Solution steps

s^{2} + 10 s + 25 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 25 = 0

s_{1, 2} = \frac{- 10 \pm 0}{2 \cdot 1}

s = \frac{- 10}{2 \cdot 1}

\frac{- 10}{2 \cdot 1} = - 5

s = - 5

The solution to the quadratic equation is:

s = - 5

4 z^{2} = 16 z

6 x^{2} - 11 x + 6 = 0

(3 x - 1) (2 x) + (2 x) = 0

2 a^{2} + 15 a + 7 = 0

x^{2} - 0.4 x - 1.2 = 0

What are the solutions to the equation s^2+10s+25=0 ?
The solutions to the equation s^2+10s+25=0 are s=-5
Find the zeros of s^2+10s+25=0
The zeros of s^2+10s+25=0 are s=-5