What are the solutions to the equation 4a^2-20a+44=-5 ?

The solutions to the equation 4a^2-20a+44=-5 are a= 5/2+sqrt(6)i,a= 5/2-sqrt(6)i

Find the zeros of 4a^2-20a+44=-5

The zeros of 4a^2-20a+44=-5 are a= 5/2+sqrt(6)i,a= 5/2-sqrt(6)i

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4 a^{2} - 20 a + 44 = - 5

a = \frac{5}{2} + 6 i, a = \frac{5}{2} - 6 i

Solution steps

4 a^{2} - 20 a + 44 = - 5

Move

5

to the left side

4 a^{2} - 20 a + 49 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 4 \cdot 49}{2 \cdot 4}

Simplify

(- 20)^{2} - 4 \cdot 4 \cdot 49 : 86 i

a_{1, 2} = \frac{- ( - 20 ) \pm 8 6 i}{2 \cdot 4}

Separate the solutions

a_{1} = \frac{- ( - 20 ) + 8 6 i}{2 \cdot 4}, a_{2} = \frac{- ( - 20 ) - 8 6 i}{2 \cdot 4}

a = \frac{- ( - 20 ) + 8 6 i}{2 \cdot 4} : \frac{5}{2} + 6 i

a = \frac{- ( - 20 ) - 8 6 i}{2 \cdot 4} : \frac{5}{2} - 6 i

The solutions to the quadratic equation are:

a = \frac{5}{2} + 6 i, a = \frac{5}{2} - 6 i

0.005 = 2 (0.005) (1 - (\frac{r}{0.005})^{2})

5 x (x - 6) = x - 30

2 a^{2} x^{2} - 6 a x = - 5

2 u^{2} - 7 u = 0

5 m^{2} + 26 m + 5 = 0

What are the solutions to the equation 4a^2-20a+44=-5 ?
The solutions to the equation 4a^2-20a+44=-5 are a= 5/2+sqrt(6)i,a= 5/2-sqrt(6)i
Find the zeros of 4a^2-20a+44=-5
The zeros of 4a^2-20a+44=-5 are a= 5/2+sqrt(6)i,a= 5/2-sqrt(6)i