What are the solutions to the equation 7+(x-4)^2=11 ?

The solutions to the equation 7+(x-4)^2=11 are x=6,x=2

Find the zeros of 7+(x-4)^2=11

The zeros of 7+(x-4)^2=11 are x=6,x=2

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7 + (x - 4)^{2} = 11

x = 6, x = 2

Solution steps

7 + (x - 4)^{2} = 11

Move

7

to the right side

(x - 4)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = 4 : x = 6

Solve

x - 4 = - 4 : x = 2

The solutions to the quadratic equation are:

x = 6, x = 2

- 4 ∣ x - 6 ∣ \geq - 20

(3 x + 2)^{2} + 64 = 0

\frac{1 + \frac{x}{y}}{\frac{x}{y}}

- x^{2} + 4 x = 0

6 p^{2} - 5 p - 11 = 5 p^{2}

What are the solutions to the equation 7+(x-4)^2=11 ?
The solutions to the equation 7+(x-4)^2=11 are x=6,x=2
Find the zeros of 7+(x-4)^2=11
The zeros of 7+(x-4)^2=11 are x=6,x=2