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Popular >

(7n+1)/3+4<= (n+2)/6

Solution

\frac{7 n + 1}{3} + 4 \leq \frac{n + 2}{6}

Solution

n \leq - \frac{24}{13}

+2

Interval Notation

(- \infty, - \frac{24}{13}]

Decimal Notation

n \leq - 1.84615 \dots

Solution steps

\frac{7 n + 1}{3} + 4 \leq \frac{n + 2}{6}

Multiply by LCM

2 (7 n + 1) + 24 \leq n + 2

Expand

2 (7 n + 1) + 24 : 14 n + 26

14 n + 26 \leq n + 2

Move

26

to the right side

14 n \leq n - 24

Move

n

to the left side

13 n \leq - 24

Divide both sides by

13

n \leq - \frac{24}{13}

Popular Examples

x^{2} + 2 x = 12

factor x^4+2x^2+x factor

x^{4} + 2 x^{2} + x

simplify 6/5+1 simplify

\frac{6}{5} + 1

15x^3+35x^2+20x>= 0

15 x^{3} + 35 x^{2} + 20 x \geq 0

5 x^{2} + 26 x - 24 = 0

Frequently Asked Questions (FAQ)

What is (7n+1)/3+4<= (n+2)/6 ?
The solution to (7n+1)/3+4<= (n+2)/6 is n<=-24/13