What is expand ((x^3-5x+4))/(x-1) ?

The solution to expand ((x^3-5x+4))/(x-1) is x^2+x-4

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expand ((x^3-5x+4))/(x-1)

expand

\frac{( x ^{3} - 5 x + 4 )}{x - 1}

x^{2} + x - 4

Solution steps

\frac{x ^{3} - 5 x + 4}{x - 1}

Factor

x^{3} - 5 x + 4 : (x - 1) (x^{2} + x - 4)

= \frac{( x - 1 ) ( x ^{2} + x - 4 )}{x - 1}

Cancel the common factor:

x - 1

= x^{2} + x - 4

\frac{d ( d - 1 ) ( d - 2 )}{6}

\frac{1}{( s + 1 ) ( s + 3 ) ( s + 5 )}

\frac{7 x}{( 2 x + 1 ) ( x - 3 )}

\frac{2 ( 3 e ^{3 π} + 1 ) ( 3 e ^{3 π} - 1 )}{e ^{6 π}}

\frac{4 x ^{3}}{( x + 1 ) ^{2} ( x ^{2} - 1 )}

What is expand ((x^3-5x+4))/(x-1) ?
The solution to expand ((x^3-5x+4))/(x-1) is x^2+x-4