What is expand (2(27-54x+36x^2-8x^3))/3 ?

The solution to expand (2(27-54x+36x^2-8x^3))/3 is -(16x^3)/3+24x^2-36x+18

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expand (2(27-54x+36x^2-8x^3))/3

expand

\frac{2 ( 27 - 54 x + 36 x ^{2} - 8 x ^{3} )}{3}

- \frac{16 x ^{3}}{3} + 24 x^{2} - 36 x + 18

Solution steps

\frac{2 ( 27 - 54 x + 36 x ^{2} - 8 x ^{3} )}{3}

Expand

2 (27 - 54 x + 36 x^{2} - 8 x^{3}) : 54 - 108 x + 72 x^{2} - 16 x^{3}

= \frac{54 - 108 x + 72 x ^{2} - 16 x ^{3}}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{54 - 108 x + 72 x ^{2} - 16 x ^{3}}{3} = \frac{54}{3} - \frac{108 x}{3} + \frac{72 x ^{2}}{3} - \frac{16 x ^{3}}{3}

= \frac{54}{3} - \frac{108 x}{3} + \frac{72 x ^{2}}{3} - \frac{16 x ^{3}}{3}

Divide the numbers:

\frac{54}{3} = 18

= 18 - \frac{108 x}{3} + \frac{72 x ^{2}}{3} - \frac{16 x ^{3}}{3}

Divide the numbers:

\frac{108}{3} = 36

= 18 - 36 x + \frac{72 x ^{2}}{3} - \frac{16 x ^{3}}{3}

Divide the numbers:

\frac{72}{3} = 24

= 18 - 36 x + 24 x^{2} - \frac{16 x ^{3}}{3}

Rewrite in standard form

= - \frac{16 x ^{3}}{3} + 24 x^{2} - 36 x + 18

(\frac{b + a}{2})^{2}

lo g_{10} (a^{6} b)

d x (e^{s i n (x)} + cos (x))

(x - 1)^{2 \circ} (x + 1)

(3 x + 2 y = 1, 6) (y = - 7 x + 19)

What is expand (2(27-54x+36x^2-8x^3))/3 ?
The solution to expand (2(27-54x+36x^2-8x^3))/3 is -(16x^3)/3+24x^2-36x+18