What are the solutions to the equation 2x^2+12x-5=0 ?

The solutions to the equation 2x^2+12x-5=0 are x=(-6+sqrt(46))/2 ,x=-(6+sqrt(46))/2

Find the zeros of 2x^2+12x-5=0

The zeros of 2x^2+12x-5=0 are x=(-6+sqrt(46))/2 ,x=-(6+sqrt(46))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} + 12 x - 5 = 0

x = \frac{- 6 + 46}{2}, x = - \frac{6 + 46}{2}

Decimal Notation

x = 0.39116 \dots, x = - 6.39116 \dots

Solution steps

2 x^{2} + 12 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 2 ( - 5 )}{2 \cdot 2}

1 2^{2} - 4 \cdot 2 (- 5) = 246

x_{1, 2} = \frac{- 12 \pm 2 46}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 12 + 2 46}{2 \cdot 2}, x_{2} = \frac{- 12 - 2 46}{2 \cdot 2}

x = \frac{- 12 + 2 46}{2 \cdot 2} : \frac{- 6 + 46}{2}

x = \frac{- 12 - 2 46}{2 \cdot 2} : - \frac{6 + 46}{2}

The solutions to the quadratic equation are:

x = \frac{- 6 + 46}{2}, x = - \frac{6 + 46}{2}

130

3 x^{2} - 7 x - 2 = 0

2 x (x + 3) + (3 - x)^{2} = 3 x (x + 1)

3 x^{2} - 9 = - 2 x

\frac{9}{- 5} + \frac{- 8}{7}

What are the solutions to the equation 2x^2+12x-5=0 ?
The solutions to the equation 2x^2+12x-5=0 are x=(-6+sqrt(46))/2 ,x=-(6+sqrt(46))/2
Find the zeros of 2x^2+12x-5=0
The zeros of 2x^2+12x-5=0 are x=(-6+sqrt(46))/2 ,x=-(6+sqrt(46))/2