What are the solutions to the equation 32x^2+18x-17=0 ?

The solutions to the equation 32x^2+18x-17=0 are x= 1/2 ,x=-17/16

Find the zeros of 32x^2+18x-17=0

The zeros of 32x^2+18x-17=0 are x= 1/2 ,x=-17/16

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32 x^{2} + 18 x - 17 = 0

x = \frac{1}{2}, x = - \frac{17}{16}

Solution steps

32 x^{2} + 18 x - 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 32 ( - 17 )}{2 \cdot 32}

1 8^{2} - 4 \cdot 32 (- 17) = 50

x_{1, 2} = \frac{- 18 \pm 50}{2 \cdot 32}

Separate the solutions

x_{1} = \frac{- 18 + 50}{2 \cdot 32}, x_{2} = \frac{- 18 - 50}{2 \cdot 32}

x = \frac{- 18 + 50}{2 \cdot 32} : \frac{1}{2}

x = \frac{- 18 - 50}{2 \cdot 32} : - \frac{17}{16}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - \frac{17}{16}

x^{2} - 6 x - 7 \geq 4

6 x^{2} - 12 x = - 3

4 m^{2} - 20 am

\frac{( 2 π ( 149.6 \cdot 1 0 ^{6} ) )}{1}

6 x^{2} + 96 x - 13 = - 13

What are the solutions to the equation 32x^2+18x-17=0 ?
The solutions to the equation 32x^2+18x-17=0 are x= 1/2 ,x=-17/16
Find the zeros of 32x^2+18x-17=0
The zeros of 32x^2+18x-17=0 are x= 1/2 ,x=-17/16