What are the solutions to the equation 25p^2+24p+9=-6p ?

The solutions to the equation 25p^2+24p+9=-6p are p=-3/5

Find the zeros of 25p^2+24p+9=-6p

The zeros of 25p^2+24p+9=-6p are p=-3/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

25 p^{2} + 24 p + 9 = - 6 p

p = - \frac{3}{5}

Decimal Notation

p = - 0.6

Solution steps

25 p^{2} + 24 p + 9 = - 6 p

Move

6 p

to the left side

25 p^{2} + 30 p + 9 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 30 \pm 3 0 ^{2} - 4 \cdot 25 \cdot 9}{2 \cdot 25}

3 0^{2} - 4 \cdot 25 \cdot 9 = 0

p_{1, 2} = \frac{- 30 \pm 0}{2 \cdot 25}

p = \frac{- 30}{2 \cdot 25}

\frac{- 30}{2 \cdot 25} = - \frac{3}{5}

p = - \frac{3}{5}

The solution to the quadratic equation is:

p = - \frac{3}{5}

x^{2} - 4 x = 4 x

5 (w - 1)^{2} = 4

x^{2} - 15 x + 7 = - 6 x - 1

x^{2} + 3 x - 68 = 3 x - 4

x^{2} - 8 x = - x

What are the solutions to the equation 25p^2+24p+9=-6p ?
The solutions to the equation 25p^2+24p+9=-6p are p=-3/5
Find the zeros of 25p^2+24p+9=-6p
The zeros of 25p^2+24p+9=-6p are p=-3/5