What are the solutions to the equation 5(w-1)^2=4 ?

The solutions to the equation 5(w-1)^2=4 are w= 2/(sqrt(5))+1,w=-2/(sqrt(5))+1

Find the zeros of 5(w-1)^2=4

The zeros of 5(w-1)^2=4 are w= 2/(sqrt(5))+1,w=-2/(sqrt(5))+1

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5 (w - 1)^{2} = 4

w = \frac{2}{5} + 1, w = - \frac{2}{5} + 1

Decimal Notation

w = 1.89442 \dots, w = 0.10557 \dots

Solution steps

5 (w - 1)^{2} = 4

Divide both sides by

5

(w - 1)^{2} = \frac{4}{5}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

w - 1 = \frac{4}{5} : w = \frac{2}{5} + 1

Solve

w - 1 = - \frac{4}{5} : w = - \frac{2}{5} + 1

The solutions to the quadratic equation are:

w = \frac{2}{5} + 1, w = - \frac{2}{5} + 1

x^{2} - 15 x + 7 = - 6 x - 1

x^{2} + 3 x - 68 = 3 x - 4

x^{2} - 8 x = - x

x^{2} - 10 x - 4 = - 2 x - 4

A (x) = x (\frac{288 - 2 x}{2})

What are the solutions to the equation 5(w-1)^2=4 ?
The solutions to the equation 5(w-1)^2=4 are w= 2/(sqrt(5))+1,w=-2/(sqrt(5))+1
Find the zeros of 5(w-1)^2=4
The zeros of 5(w-1)^2=4 are w= 2/(sqrt(5))+1,w=-2/(sqrt(5))+1