What are the solutions to the equation -1/4 (x-4)^2+8=0 ?

The solutions to the equation -1/4 (x-4)^2+8=0 are x=4sqrt(2)+4,x=-4sqrt(2)+4

Find the zeros of -1/4 (x-4)^2+8=0

The zeros of -1/4 (x-4)^2+8=0 are x=4sqrt(2)+4,x=-4sqrt(2)+4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- \frac{1}{4} (x - 4)^{2} + 8 = 0

x = 42 + 4, x = - 42 + 4

Decimal Notation

x = 9.65685 \dots, x = - 1.65685 \dots

Solution steps

- \frac{1}{4} (x - 4)^{2} + 8 = 0

Move

8

to the right side

- \frac{1}{4} (x - 4)^{2} = - 8

Multiply both sides by

- 4

(x - 4)^{2} = 32

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = 32 : x = 42 + 4

Solve

x - 4 = - 32 : x = - 42 + 4

The solutions to the quadratic equation are:

x = 42 + 4, x = - 42 + 4

x^{2} + 2 x = - 2 x

x^{2} - 3 x - 4 = - 3 x

4 v^{2} - 4 v - 15 = 0

x^{2} + 5 x - 3 = - 4 x - 3

x^{2} - 8 x + 48 = 0

What are the solutions to the equation -1/4 (x-4)^2+8=0 ?
The solutions to the equation -1/4 (x-4)^2+8=0 are x=4sqrt(2)+4,x=-4sqrt(2)+4
Find the zeros of -1/4 (x-4)^2+8=0
The zeros of -1/4 (x-4)^2+8=0 are x=4sqrt(2)+4,x=-4sqrt(2)+4