What are the solutions to the equation 2(5x+2)^2=48 ?

The solutions to the equation 2(5x+2)^2=48 are x=(2sqrt(6)-2)/5 ,x=(-2sqrt(6)-2)/5

Find the zeros of 2(5x+2)^2=48

The zeros of 2(5x+2)^2=48 are x=(2sqrt(6)-2)/5 ,x=(-2sqrt(6)-2)/5

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2 (5 x + 2)^{2} = 48

x = \frac{2 6 - 2}{5}, x = \frac{- 2 6 - 2}{5}

Decimal Notation

x = 0.57979 \dots, x = - 1.37979 \dots

Solution steps

2 (5 x + 2)^{2} = 48

Divide both sides by

2

(5 x + 2)^{2} = 24

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 x + 2 = 24 : x = \frac{2 6 - 2}{5}

Solve

5 x + 2 = - 24 : x = \frac{- 2 6 - 2}{5}

The solutions to the quadratic equation are:

x = \frac{2 6 - 2}{5}, x = \frac{- 2 6 - 2}{5}

v^{2} + 5 v = - 4

- 10 x^{2} - 12 x = - 9982

x, x^{2} + k x + k + 8 = 0

4 b^{2} + 2 b - 2 = 3 b

x^{2} - 9 x - 9 = - 5 x - 4

What are the solutions to the equation 2(5x+2)^2=48 ?
The solutions to the equation 2(5x+2)^2=48 are x=(2sqrt(6)-2)/5 ,x=(-2sqrt(6)-2)/5
Find the zeros of 2(5x+2)^2=48
The zeros of 2(5x+2)^2=48 are x=(2sqrt(6)-2)/5 ,x=(-2sqrt(6)-2)/5