What are the solutions to the equation 1+4x+4x^2=0 ?

The solutions to the equation 1+4x+4x^2=0 are x=-1/2

Find the zeros of 1+4x+4x^2=0

The zeros of 1+4x+4x^2=0 are x=-1/2

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1 + 4 x + 4 x^{2} = 0

x = - \frac{1}{2}

Decimal Notation

x = - 0.5

Solution steps

1 + 4 x + 4 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} + 4 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

4^{2} - 4 \cdot 4 \cdot 1 = 0

x_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 4}

x = \frac{- 4}{2 \cdot 4}

\frac{- 4}{2 \cdot 4} = - \frac{1}{2}

x = - \frac{1}{2}

The solution to the quadratic equation is:

x = - \frac{1}{2}

5 b^{2} - 30 b + 20 = - b

1 - 0.75 x + 0.1 x^{2} = 0

x^{0} = x^{2} + 5 x + 8

x, d^{2} = 2 x^{2} + 2 x^{2}

a, 4 a^{2} - 6 ab = 0

What are the solutions to the equation 1+4x+4x^2=0 ?
The solutions to the equation 1+4x+4x^2=0 are x=-1/2
Find the zeros of 1+4x+4x^2=0
The zeros of 1+4x+4x^2=0 are x=-1/2