What are the solutions to the equation 5b^2-30b+20=-b ?

The solutions to the equation 5b^2-30b+20=-b are b=5,b= 4/5

Find the zeros of 5b^2-30b+20=-b

The zeros of 5b^2-30b+20=-b are b=5,b= 4/5

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5 b^{2} - 30 b + 20 = - b

b = 5, b = \frac{4}{5}

Decimal Notation

b = 5, b = 0.8

Solution steps

5 b^{2} - 30 b + 20 = - b

Move

b

to the left side

5 b^{2} - 29 b + 20 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 29 ) \pm ( - 29 ) ^{2} - 4 \cdot 5 \cdot 20}{2 \cdot 5}

(- 29)^{2} - 4 \cdot 5 \cdot 20 = 21

b_{1, 2} = \frac{- ( - 29 ) \pm 21}{2 \cdot 5}

Separate the solutions

b_{1} = \frac{- ( - 29 ) + 21}{2 \cdot 5}, b_{2} = \frac{- ( - 29 ) - 21}{2 \cdot 5}

b = \frac{- ( - 29 ) + 21}{2 \cdot 5} : 5

b = \frac{- ( - 29 ) - 21}{2 \cdot 5} : \frac{4}{5}

The solutions to the quadratic equation are:

b = 5, b = \frac{4}{5}

1 - 0.75 x + 0.1 x^{2} = 0

x^{0} = x^{2} + 5 x + 8

x, d^{2} = 2 x^{2} + 2 x^{2}

a, 4 a^{2} - 6 ab = 0

3 x^{2} + 8 x - 10 = - 8

What are the solutions to the equation 5b^2-30b+20=-b ?
The solutions to the equation 5b^2-30b+20=-b are b=5,b= 4/5
Find the zeros of 5b^2-30b+20=-b
The zeros of 5b^2-30b+20=-b are b=5,b= 4/5