What are the solutions to the equation 15d^2+31d+15=5 ?

The solutions to the equation 15d^2+31d+15=5 are d=-2/5 ,d=-5/3

Find the zeros of 15d^2+31d+15=5

The zeros of 15d^2+31d+15=5 are d=-2/5 ,d=-5/3

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15 d^{2} + 31 d + 15 = 5

d = - \frac{2}{5}, d = - \frac{5}{3}

Decimal Notation

d = - 0.4, d = - 1.66666 \dots

Solution steps

15 d^{2} + 31 d + 15 = 5

Move

5

to the left side

15 d^{2} + 31 d + 10 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- 31 \pm 3 1 ^{2} - 4 \cdot 15 \cdot 10}{2 \cdot 15}

3 1^{2} - 4 \cdot 15 \cdot 10 = 19

d_{1, 2} = \frac{- 31 \pm 19}{2 \cdot 15}

Separate the solutions

d_{1} = \frac{- 31 + 19}{2 \cdot 15}, d_{2} = \frac{- 31 - 19}{2 \cdot 15}

d = \frac{- 31 + 19}{2 \cdot 15} : - \frac{2}{5}

d = \frac{- 31 - 19}{2 \cdot 15} : - \frac{5}{3}

The solutions to the quadratic equation are:

d = - \frac{2}{5}, d = - \frac{5}{3}

2 x^{2} + 20 x - 6 = 0

2 a^{2} + a - 21 = 0

4 r^{2} - 5 r - 5 = 3 r

5 p^{2} - 13 p + 6 = p^{2}

2 x^{2} + 7 x - 7 = 2

What are the solutions to the equation 15d^2+31d+15=5 ?
The solutions to the equation 15d^2+31d+15=5 are d=-2/5 ,d=-5/3
Find the zeros of 15d^2+31d+15=5
The zeros of 15d^2+31d+15=5 are d=-2/5 ,d=-5/3