What are the solutions to the equation 4r^2-5r-5=3r ?

The solutions to the equation 4r^2-5r-5=3r are r= 5/2 ,r=-1/2

Find the zeros of 4r^2-5r-5=3r

The zeros of 4r^2-5r-5=3r are r= 5/2 ,r=-1/2

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4 r^{2} - 5 r - 5 = 3 r

r = \frac{5}{2}, r = - \frac{1}{2}

Decimal Notation

r = 2.5, r = - 0.5

Solution steps

4 r^{2} - 5 r - 5 = 3 r

Move

3 r

to the left side

4 r^{2} - 8 r - 5 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 4 ( - 5 )}{2 \cdot 4}

(- 8)^{2} - 4 \cdot 4 (- 5) = 12

r_{1, 2} = \frac{- ( - 8 ) \pm 12}{2 \cdot 4}

Separate the solutions

r_{1} = \frac{- ( - 8 ) + 12}{2 \cdot 4}, r_{2} = \frac{- ( - 8 ) - 12}{2 \cdot 4}

r = \frac{- ( - 8 ) + 12}{2 \cdot 4} : \frac{5}{2}

r = \frac{- ( - 8 ) - 12}{2 \cdot 4} : - \frac{1}{2}

The solutions to the quadratic equation are:

r = \frac{5}{2}, r = - \frac{1}{2}

5 p^{2} - 13 p + 6 = p^{2}

2 x^{2} + 7 x - 7 = 2

x, x^{2} + y^{2} + z^{2} = z

2 x^{2} - 10 - 8 x = 0

4 x^{2} + 140 x - 296 = 0

What are the solutions to the equation 4r^2-5r-5=3r ?
The solutions to the equation 4r^2-5r-5=3r are r= 5/2 ,r=-1/2
Find the zeros of 4r^2-5r-5=3r
The zeros of 4r^2-5r-5=3r are r= 5/2 ,r=-1/2