What are the solutions to the equation 36x^2+24x+12=0 ?

The solutions to the equation 36x^2+24x+12=0 are x=-1/3+i(sqrt(2))/3 ,x=-1/3-i(sqrt(2))/3

Find the zeros of 36x^2+24x+12=0

The zeros of 36x^2+24x+12=0 are x=-1/3+i(sqrt(2))/3 ,x=-1/3-i(sqrt(2))/3

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36 x^{2} + 24 x + 12 = 0

x = - \frac{1}{3} + i \frac{2}{3}, x = - \frac{1}{3} - i \frac{2}{3}

Solution steps

36 x^{2} + 24 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 36 \cdot 12}{2 \cdot 36}

Simplify

2 4^{2} - 4 \cdot 36 \cdot 12 : 242 i

x_{1, 2} = \frac{- 24 \pm 24 2 i}{2 \cdot 36}

Separate the solutions

x_{1} = \frac{- 24 + 24 2 i}{2 \cdot 36}, x_{2} = \frac{- 24 - 24 2 i}{2 \cdot 36}

x = \frac{- 24 + 24 2 i}{2 \cdot 36} : - \frac{1}{3} + i \frac{2}{3}

x = \frac{- 24 - 24 2 i}{2 \cdot 36} : - \frac{1}{3} - i \frac{2}{3}

The solutions to the quadratic equation are:

x = - \frac{1}{3} + i \frac{2}{3}, x = - \frac{1}{3} - i \frac{2}{3}

20 x^{2} - 26 x + 8 = 0

x^{2} - \frac{11}{3} x - 2 = 0

25 k^{2} + 20 k + 3 = - 1

x, 2 x^{2} y - 2 x y = 0

y, x^{3} + x y^{2} - 2 y^{2} = 0

What are the solutions to the equation 36x^2+24x+12=0 ?
The solutions to the equation 36x^2+24x+12=0 are x=-1/3+i(sqrt(2))/3 ,x=-1/3-i(sqrt(2))/3
Find the zeros of 36x^2+24x+12=0
The zeros of 36x^2+24x+12=0 are x=-1/3+i(sqrt(2))/3 ,x=-1/3-i(sqrt(2))/3