What are the solutions to the equation 3m^2+20m+25=0 ?

The solutions to the equation 3m^2+20m+25=0 are m=-5/3 ,m=-5

Find the zeros of 3m^2+20m+25=0

The zeros of 3m^2+20m+25=0 are m=-5/3 ,m=-5

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3 m^{2} + 20 m + 25 = 0

m = - \frac{5}{3}, m = - 5

Decimal Notation

m = - 1.66666 \dots, m = - 5

Solution steps

3 m^{2} + 20 m + 25 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 3 \cdot 25}{2 \cdot 3}

2 0^{2} - 4 \cdot 3 \cdot 25 = 10

m_{1, 2} = \frac{- 20 \pm 10}{2 \cdot 3}

Separate the solutions

m_{1} = \frac{- 20 + 10}{2 \cdot 3}, m_{2} = \frac{- 20 - 10}{2 \cdot 3}

m = \frac{- 20 + 10}{2 \cdot 3} : - \frac{5}{3}

m = \frac{- 20 - 10}{2 \cdot 3} : - 5

The solutions to the quadratic equation are:

m = - \frac{5}{3}, m = - 5

4 p^{2} + 6 p + 1 = 2 p

- 16 x^{2} + 14 x + 4 = 0

- x^{2} + 6 x = - 1

9^{2} + x^{2} = 1 8^{2}

x^{2} + 55 = - 16 x - 5

What are the solutions to the equation 3m^2+20m+25=0 ?
The solutions to the equation 3m^2+20m+25=0 are m=-5/3 ,m=-5
Find the zeros of 3m^2+20m+25=0
The zeros of 3m^2+20m+25=0 are m=-5/3 ,m=-5