What are the solutions to the equation (2-3d)(4-3d)=0 ?

The solutions to the equation (2-3d)(4-3d)=0 are d= 2/3 ,d= 4/3

Find the zeros of (2-3d)(4-3d)=0

The zeros of (2-3d)(4-3d)=0 are d= 2/3 ,d= 4/3

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(2 - 3 d) (4 - 3 d) = 0

d = \frac{2}{3}, d = \frac{4}{3}

Decimal Notation

d = 0.66666 \dots, d = 1.33333 \dots

Solution steps

(2 - 3 d) (4 - 3 d) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 - 3 d = 0 or 4 - 3 d = 0

Solve

2 - 3 d = 0 : d = \frac{2}{3}

Solve

4 - 3 d = 0 : d = \frac{4}{3}

The solutions to the quadratic equation are:

d = \frac{2}{3}, d = \frac{4}{3}

(x + 3)^{2} = 2

x^{2} - 3 x - \frac{9}{4} = 12

2 x^{2} - 12 x + 17

3 x^{2} + x + 4 = - 9 x + 1

x, x^{2} + (1 - y)^{2} + 5 = 0

What are the solutions to the equation (2-3d)(4-3d)=0 ?
The solutions to the equation (2-3d)(4-3d)=0 are d= 2/3 ,d= 4/3
Find the zeros of (2-3d)(4-3d)=0
The zeros of (2-3d)(4-3d)=0 are d= 2/3 ,d= 4/3