What are the solutions to the equation d^2=5^2-3^2 ?

The solutions to the equation d^2=5^2-3^2 are d=4,d=-4

Find the zeros of d^2=5^2-3^2

The zeros of d^2=5^2-3^2 are d=4,d=-4

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d^{2} = 5^{2} - 3^{2}

d = 4, d = - 4

Solution steps

d^{2} = 5^{2} - 3^{2}

Simplify

5^{2} - 3^{2} : 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

d = 16, d = - 16

16 = 4

- 16 = - 4

d = 4, d = - 4

(m - 3) x^{2} + 4 m - 3 x = m x - 1

(3 w + 4) (2 w - 7) = 0

\frac{x ^{2} - 6}{4} = 0

30 x^{2} - 420 x + 1470 = 0

- 3 x^{2} + 7 x = - 2 x - 8

What are the solutions to the equation d^2=5^2-3^2 ?
The solutions to the equation d^2=5^2-3^2 are d=4,d=-4
Find the zeros of d^2=5^2-3^2
The zeros of d^2=5^2-3^2 are d=4,d=-4