What are the solutions to the equation 1/25-x^2=0 ?

The solutions to the equation 1/25-x^2=0 are x= 1/5 ,x=-1/5

Find the zeros of 1/25-x^2=0

The zeros of 1/25-x^2=0 are x= 1/5 ,x=-1/5

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\frac{1}{25} - x^{2} = 0

x = \frac{1}{5}, x = - \frac{1}{5}

Decimal Notation

x = 0.2, x = - 0.2

Solution steps

\frac{1}{25} - x^{2} = 0

Move

\frac{1}{25}

to the right side

- x^{2} = - \frac{1}{25}

Divide both sides by

- 1

x^{2} = \frac{1}{25}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{25}, x = - \frac{1}{25}

\frac{1}{25} = \frac{1}{5}

- \frac{1}{25} = - \frac{1}{5}

x = \frac{1}{5}, x = - \frac{1}{5}

3 x^{2} + 6 = 11 x

x^{2} + (x - 3)^{2} = 549

m^{2} - 8 m - 20 = 0

3 (a - 5) (a + 2) = 0

y, z = x^{2} y^{2} + x^{3} y

What are the solutions to the equation 1/25-x^2=0 ?
The solutions to the equation 1/25-x^2=0 are x= 1/5 ,x=-1/5
Find the zeros of 1/25-x^2=0
The zeros of 1/25-x^2=0 are x= 1/5 ,x=-1/5