What are the solutions to the equation (2x-1)(x-3)=7 ?

The solutions to the equation (2x-1)(x-3)=7 are x=4,x=-1/2

Find the zeros of (2x-1)(x-3)=7

The zeros of (2x-1)(x-3)=7 are x=4,x=-1/2

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(2 x - 1) (x - 3) = 7

x = 4, x = - \frac{1}{2}

Decimal Notation

x = 4, x = - 0.5

Solution steps

(2 x - 1) (x - 3) = 7

Expand

(2 x - 1) (x - 3) : 2 x^{2} - 7 x + 3

2 x^{2} - 7 x + 3 = 7

Move

7

to the left side

2 x^{2} - 7 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 2 ( - 4 )}{2 \cdot 2}

(- 7)^{2} - 4 \cdot 2 (- 4) = 9

x_{1, 2} = \frac{- ( - 7 ) \pm 9}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 9}{2 \cdot 2}, x_{2} = \frac{- ( - 7 ) - 9}{2 \cdot 2}

x = \frac{- ( - 7 ) + 9}{2 \cdot 2} : 4

x = \frac{- ( - 7 ) - 9}{2 \cdot 2} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = 4, x = - \frac{1}{2}

x, 2 x^{2} + 2 y^{2} - z + 1 = 0

9 x^{2} + 48 x = 36

350 + x - 2 x^{2} = 50 + x + x^{2}

x, y^{2} + 2 x y - x^{2} = 0

3 t^{2} - 5 t + 2 = 0

What are the solutions to the equation (2x-1)(x-3)=7 ?
The solutions to the equation (2x-1)(x-3)=7 are x=4,x=-1/2
Find the zeros of (2x-1)(x-3)=7
The zeros of (2x-1)(x-3)=7 are x=4,x=-1/2