What are the solutions to the equation 45x^2-36=0 ?

The solutions to the equation 45x^2-36=0 are x= 2/(sqrt(5)),x=-2/(sqrt(5))

Find the zeros of 45x^2-36=0

The zeros of 45x^2-36=0 are x= 2/(sqrt(5)),x=-2/(sqrt(5))

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45 x^{2} - 36 = 0

x = \frac{2}{5}, x = - \frac{2}{5}

Decimal Notation

x = 0.89442 \dots, x = - 0.89442 \dots

Solution steps

45 x^{2} - 36 = 0

Move

36

to the right side

45 x^{2} = 36

Divide both sides by

45

x^{2} = \frac{4}{5}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{4}{5}, x = - \frac{4}{5}

\frac{4}{5} = \frac{2}{5}

- \frac{4}{5} = - \frac{2}{5}

x = \frac{2}{5}, x = - \frac{2}{5}

x (3 x + 6) = 140

x, f (x + 1) = (x + 1)^{2} - 4

11 x^{2} - 12 x = 0

6 x^{2} - 3 x - 7 = 0

(x + 8)^{2} + (x - 8)^{2} = x^{2} + 132

What are the solutions to the equation 45x^2-36=0 ?
The solutions to the equation 45x^2-36=0 are x= 2/(sqrt(5)),x=-2/(sqrt(5))
Find the zeros of 45x^2-36=0
The zeros of 45x^2-36=0 are x= 2/(sqrt(5)),x=-2/(sqrt(5))