What are the solutions to the equation x^2-26x=60-x^2 ?

The solutions to the equation x^2-26x=60-x^2 are x=15,x=-2

Find the zeros of x^2-26x=60-x^2

The zeros of x^2-26x=60-x^2 are x=15,x=-2

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x^{2} - 26 x = 60 - x^{2}

x = 15, x = - 2

Solution steps

x^{2} - 26 x = 60 - x^{2}

Move

x^{2}

to the left side

2 x^{2} - 26 x = 60

Move

60

to the left side

2 x^{2} - 26 x - 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 26 ) \pm ( - 26 ) ^{2} - 4 \cdot 2 ( - 60 )}{2 \cdot 2}

(- 26)^{2} - 4 \cdot 2 (- 60) = 34

x_{1, 2} = \frac{- ( - 26 ) \pm 34}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 26 ) + 34}{2 \cdot 2}, x_{2} = \frac{- ( - 26 ) - 34}{2 \cdot 2}

x = \frac{- ( - 26 ) + 34}{2 \cdot 2} : 15

x = \frac{- ( - 26 ) - 34}{2 \cdot 2} : - 2

The solutions to the quadratic equation are:

x = 15, x = - 2

8 m^{2} + 20 m = 12

(2 x - 3)^{2} - 8 = 0

a^{2} - 4 a - 32 = 0

(4 x - 3)^{2} - (x - 1) (x - 9) = 0

x^{2} + 10 x + 28

What are the solutions to the equation x^2-26x=60-x^2 ?
The solutions to the equation x^2-26x=60-x^2 are x=15,x=-2
Find the zeros of x^2-26x=60-x^2
The zeros of x^2-26x=60-x^2 are x=15,x=-2