What are the solutions to the equation 5x^2-21x-5=-7x-2 ?

The solutions to the equation 5x^2-21x-5=-7x-2 are x=3,x=-1/5

Find the zeros of 5x^2-21x-5=-7x-2

The zeros of 5x^2-21x-5=-7x-2 are x=3,x=-1/5

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5 x^{2} - 21 x - 5 = - 7 x - 2

x = 3, x = - \frac{1}{5}

Decimal Notation

x = 3, x = - 0.2

Solution steps

5 x^{2} - 21 x - 5 = - 7 x - 2

Move

2

to the left side

5 x^{2} - 21 x - 3 = - 7 x

Move

7 x

to the left side

5 x^{2} - 14 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 5 ( - 3 )}{2 \cdot 5}

(- 14)^{2} - 4 \cdot 5 (- 3) = 16

x_{1, 2} = \frac{- ( - 14 ) \pm 16}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 16}{2 \cdot 5}, x_{2} = \frac{- ( - 14 ) - 16}{2 \cdot 5}

x = \frac{- ( - 14 ) + 16}{2 \cdot 5} : 3

x = \frac{- ( - 14 ) - 16}{2 \cdot 5} : - \frac{1}{5}

The solutions to the quadratic equation are:

x = 3, x = - \frac{1}{5}

5 x^{2} + 9 x - 6 = 10 x

x, x^{2} - 49 = 0

8 x^{2} + 2 x = 7 x

(x - 6) (x - 3) = 4

(6 - x)^{2} - 1 = 0

What are the solutions to the equation 5x^2-21x-5=-7x-2 ?
The solutions to the equation 5x^2-21x-5=-7x-2 are x=3,x=-1/5
Find the zeros of 5x^2-21x-5=-7x-2
The zeros of 5x^2-21x-5=-7x-2 are x=3,x=-1/5