What are the solutions to the equation 3x^2-sqrt(3)(2sqrt(3)x+4sqrt(3))=0 ?

The solutions to the equation 3x^2-sqrt(3)(2sqrt(3)x+4sqrt(3))=0 are x=1+sqrt(5),x=1-sqrt(5)

Find the zeros of 3x^2-sqrt(3)(2sqrt(3)x+4sqrt(3))=0

The zeros of 3x^2-sqrt(3)(2sqrt(3)x+4sqrt(3))=0 are x=1+sqrt(5),x=1-sqrt(5)

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3 x^{2} - 3 (23 x + 43) = 0

x = 1 + 5, x = 1 - 5

Decimal Notation

x = 3.23606 \dots, x = - 1.23606 \dots

Solution steps

3 x^{2} - 3 (23 x + 43) = 0

Expand

3 x^{2} - 3 (23 x + 43) : 3 x^{2} - 6 x - 12

3 x^{2} - 6 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 ( - 12 )}{2 \cdot 3}

(- 6)^{2} - 4 \cdot 3 (- 12) = 65

x_{1, 2} = \frac{- ( - 6 ) \pm 6 5}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 6 5}{2 \cdot 3}, x_{2} = \frac{- ( - 6 ) - 6 5}{2 \cdot 3}

x = \frac{- ( - 6 ) + 6 5}{2 \cdot 3} : 1 + 5

x = \frac{- ( - 6 ) - 6 5}{2 \cdot 3} : 1 - 5

The solutions to the quadratic equation are:

x = 1 + 5, x = 1 - 5

[7 - x^{2}] = 10

x^{2} + 1 = 3 - x^{2}

t^{2} - 3 t - 2 = 0

x, (x - m)^{2} = 6 - m

(2 x + 15) (9 + 2 x) - (15) (9) = 100

What are the solutions to the equation 3x^2-sqrt(3)(2sqrt(3)x+4sqrt(3))=0 ?
The solutions to the equation 3x^2-sqrt(3)(2sqrt(3)x+4sqrt(3))=0 are x=1+sqrt(5),x=1-sqrt(5)
Find the zeros of 3x^2-sqrt(3)(2sqrt(3)x+4sqrt(3))=0
The zeros of 3x^2-sqrt(3)(2sqrt(3)x+4sqrt(3))=0 are x=1+sqrt(5),x=1-sqrt(5)