What are the solutions to the equation (b-1/3)^2= 4/9 ?

The solutions to the equation (b-1/3)^2= 4/9 are b=1,b=-1/3

Find the zeros of (b-1/3)^2= 4/9

The zeros of (b-1/3)^2= 4/9 are b=1,b=-1/3

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(b - \frac{1}{3})^{2} = \frac{4}{9}

b = 1, b = - \frac{1}{3}

Decimal Notation

b = 1, b = - 0.33333 \dots

Solution steps

(b - \frac{1}{3})^{2} = \frac{4}{9}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

b - \frac{1}{3} = \frac{4}{9} : b = 1

Solve

b - \frac{1}{3} = - \frac{4}{9} : b = - \frac{1}{3}

The solutions to the quadratic equation are:

b = 1, b = - \frac{1}{3}

- x^{2} - 4 x - 8 = 0

- 3 x^{2} + 80 x + 27 = 0

y^{2} - 4 y - 96 = 0

y, y^{2} = c x^{4} + 3 x

3 (x - 7)^{2} = 12

What are the solutions to the equation (b-1/3)^2= 4/9 ?
The solutions to the equation (b-1/3)^2= 4/9 are b=1,b=-1/3
Find the zeros of (b-1/3)^2= 4/9
The zeros of (b-1/3)^2= 4/9 are b=1,b=-1/3