What are the solutions to the equation 4x^2+1-2x^2+2=8 ?

The solutions to the equation 4x^2+1-2x^2+2=8 are x=sqrt(5/2),x=-sqrt(5/2)

Find the zeros of 4x^2+1-2x^2+2=8

The zeros of 4x^2+1-2x^2+2=8 are x=sqrt(5/2),x=-sqrt(5/2)

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4 x^{2} + 1 - 2 x^{2} + 2 = 8

x = \frac{5}{2}, x = - \frac{5}{2}

Decimal Notation

x = 1.58113 \dots, x = - 1.58113 \dots

Solution steps

4 x^{2} + 1 - 2 x^{2} + 2 = 8

Move

1

to the right side

4 x^{2} - 2 x^{2} + 2 = 7

Move

2

to the right side

4 x^{2} - 2 x^{2} = 5

Add similar elements:

4 x^{2} - 2 x^{2} = 2 x^{2}

2 x^{2} = 5

Divide both sides by

2

x^{2} = \frac{5}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{5}{2}, x = - \frac{5}{2}

x^{2} - 2 x - \frac{1}{4} = 0

3 u^{2} - 2 = 5 u

x^{2} + (\frac{2}{2})^{2} = 1

- 3 x^{2} + 6 x + 1 = 0

- 2 y^{2} + 30 y = 0

What are the solutions to the equation 4x^2+1-2x^2+2=8 ?
The solutions to the equation 4x^2+1-2x^2+2=8 are x=sqrt(5/2),x=-sqrt(5/2)
Find the zeros of 4x^2+1-2x^2+2=8
The zeros of 4x^2+1-2x^2+2=8 are x=sqrt(5/2),x=-sqrt(5/2)