What are the solutions to the equation 2^2+b^2=9^2 ?

The solutions to the equation 2^2+b^2=9^2 are b=sqrt(77),b=-sqrt(77)

Find the zeros of 2^2+b^2=9^2

The zeros of 2^2+b^2=9^2 are b=sqrt(77),b=-sqrt(77)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2^{2} + b^{2} = 9^{2}

b = 77, b = - 77

Decimal Notation

b = 8.77496 \dots, b = - 8.77496 \dots

Solution steps

2^{2} + b^{2} = 9^{2}

Move

2^{2}

to the right side

b^{2} = 77

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 77, b = - 77

y^{2} - 4 y - 3 = 0

3 a^{2} - 5 = 70

x^{2} + 8 x + 16 = 144

t, r (t) = 300 t - 300 t^{2}

1 7^{2} = x^{2} + (x + 7)^{2}

What are the solutions to the equation 2^2+b^2=9^2 ?
The solutions to the equation 2^2+b^2=9^2 are b=sqrt(77),b=-sqrt(77)
Find the zeros of 2^2+b^2=9^2
The zeros of 2^2+b^2=9^2 are b=sqrt(77),b=-sqrt(77)