What are the solutions to the equation -6+8x-x^2=0 ?

The solutions to the equation -6+8x-x^2=0 are x=4-sqrt(10),x=4+sqrt(10)

Find the zeros of -6+8x-x^2=0

The zeros of -6+8x-x^2=0 are x=4-sqrt(10),x=4+sqrt(10)

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- 6 + 8 x - x^{2} = 0

x = 4 - 10, x = 4 + 10

Decimal Notation

x = 0.83772 \dots, x = 7.16227 \dots

Solution steps

- 6 + 8 x - x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 8 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 1 ) ( - 6 )}{2 ( - 1 )}

8^{2} - 4 (- 1) (- 6) = 210

x_{1, 2} = \frac{- 8 \pm 2 10}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 8 + 2 10}{2 ( - 1 )}, x_{2} = \frac{- 8 - 2 10}{2 ( - 1 )}

x = \frac{- 8 + 2 10}{2 ( - 1 )} : 4 - 10

x = \frac{- 8 - 2 10}{2 ( - 1 )} : 4 + 10

The solutions to the quadratic equation are:

x = 4 - 10, x = 4 + 10

4 x (x - 5) = 0

a, (a + 2 d)^{2} = a^{2} + (a + d)^{2}

24 x^{2} + 128 x + 168 = 100 x^{2} + 40 x + 4

4 p^{2} - 78 = 11 p

4 x^{2} - 5 x - 6 = 0

What are the solutions to the equation -6+8x-x^2=0 ?
The solutions to the equation -6+8x-x^2=0 are x=4-sqrt(10),x=4+sqrt(10)
Find the zeros of -6+8x-x^2=0
The zeros of -6+8x-x^2=0 are x=4-sqrt(10),x=4+sqrt(10)