What are the solutions to the equation 25x^2=40x-16 ?

The solutions to the equation 25x^2=40x-16 are x= 4/5

Find the zeros of 25x^2=40x-16

The zeros of 25x^2=40x-16 are x= 4/5

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25 x^{2} = 40 x - 16

x = \frac{4}{5}

Decimal Notation

x = 0.8

Solution steps

25 x^{2} = 40 x - 16

Move

16

to the left side

25 x^{2} + 16 = 40 x

Move

40 x

to the left side

25 x^{2} + 16 - 40 x = 0

Write in the standard form

a x^{2} + b x + c = 0

25 x^{2} - 40 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 25 \cdot 16}{2 \cdot 25}

(- 40)^{2} - 4 \cdot 25 \cdot 16 = 0

x_{1, 2} = \frac{- ( - 40 ) \pm 0}{2 \cdot 25}

x = \frac{- ( - 40 )}{2 \cdot 25}

\frac{- ( - 40 )}{2 \cdot 25} = \frac{4}{5}

x = \frac{4}{5}

The solution to the quadratic equation is:

x = \frac{4}{5}

38^{2} + 26^{2} = c^{2}

x, 3 x^{2} - 4 x + 3 = 0

2 x^{2} - 5 x - 2 = - 4 x + 1

x^{2} + 4 x = 1

2 x + 5 x^{2} = 1

What are the solutions to the equation 25x^2=40x-16 ?
The solutions to the equation 25x^2=40x-16 are x= 4/5
Find the zeros of 25x^2=40x-16
The zeros of 25x^2=40x-16 are x= 4/5