What are the solutions to the equation (x-3)^2+8=12 ?

The solutions to the equation (x-3)^2+8=12 are x=5,x=1

Find the zeros of (x-3)^2+8=12

The zeros of (x-3)^2+8=12 are x=5,x=1

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(x - 3)^{2} + 8 = 12

x = 5, x = 1

Solution steps

(x - 3)^{2} + 8 = 12

Move

8

to the right side

(x - 3)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = 4 : x = 5

Solve

x - 3 = - 4 : x = 1

The solutions to the quadratic equation are:

x = 5, x = 1

4 x^{2} - 35 x + 24 = 0

ω, \frac{π}{4} \cdot 2 0^{2} \cdot 50 = \frac{π}{4} ω^{2} \cdot 60

- 2 x = 5 + 2 x + 3 x^{2}

28090 = 25000 (1 + \frac{r}{100})^{2}

(x + 4)^{2} = 361

What are the solutions to the equation (x-3)^2+8=12 ?
The solutions to the equation (x-3)^2+8=12 are x=5,x=1
Find the zeros of (x-3)^2+8=12
The zeros of (x-3)^2+8=12 are x=5,x=1