What are the solutions to the equation q^2+5q-36=0 ?

The solutions to the equation q^2+5q-36=0 are q=4,q=-9

Find the zeros of q^2+5q-36=0

The zeros of q^2+5q-36=0 are q=4,q=-9

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q^{2} + 5 q - 36 = 0

q = 4, q = - 9

Solution steps

q^{2} + 5 q - 36 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 36 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 36) = 13

q_{1, 2} = \frac{- 5 \pm 13}{2 \cdot 1}

Separate the solutions

q_{1} = \frac{- 5 + 13}{2 \cdot 1}, q_{2} = \frac{- 5 - 13}{2 \cdot 1}

q = \frac{- 5 + 13}{2 \cdot 1} : 4

q = \frac{- 5 - 13}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

q = 4, q = - 9

- 5 x^{2} + 8 x = 9

L^{2} - 10 L + 24 = 0

0.15 c^{2} + 4.86072 c - 2.5284 = 0

x^{2} + 0.1 x + 4 = 0

x^{2} - 300 x + 14400 = 0

What are the solutions to the equation q^2+5q-36=0 ?
The solutions to the equation q^2+5q-36=0 are q=4,q=-9
Find the zeros of q^2+5q-36=0
The zeros of q^2+5q-36=0 are q=4,q=-9