What are the solutions to the equation 4y^2-4y+y=0 ?

The solutions to the equation 4y^2-4y+y=0 are y= 3/4 ,y=0

Find the zeros of 4y^2-4y+y=0

The zeros of 4y^2-4y+y=0 are y= 3/4 ,y=0

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4 y^{2} - 4 y + y = 0

y = \frac{3}{4}, y = 0

Decimal Notation

y = 0.75, y = 0

Solution steps

4 y^{2} - 4 y + y = 0

Refine

4 y^{2} - 3 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

(- 3)^{2} - 4 \cdot 4 \cdot 0 = 3

y_{1, 2} = \frac{- ( - 3 ) \pm 3}{2 \cdot 4}

Separate the solutions

y_{1} = \frac{- ( - 3 ) + 3}{2 \cdot 4}, y_{2} = \frac{- ( - 3 ) - 3}{2 \cdot 4}

y = \frac{- ( - 3 ) + 3}{2 \cdot 4} : \frac{3}{4}

y = \frac{- ( - 3 ) - 3}{2 \cdot 4} : 0

The solutions to the quadratic equation are:

y = \frac{3}{4}, y = 0

x^{2} - 9 x + 20 = 0

x^{2} - 300 x + 17600 = 0

3 x^{2} + 63 x + 12 = 39

x, 2 x^{2} + 2 y^{2} + 2 z^{2} = 8 x - 16 z + 1

y, y^{2} = x^{3} - 5 x + 5

What are the solutions to the equation 4y^2-4y+y=0 ?
The solutions to the equation 4y^2-4y+y=0 are y= 3/4 ,y=0
Find the zeros of 4y^2-4y+y=0
The zeros of 4y^2-4y+y=0 are y= 3/4 ,y=0