What are the solutions to the equation x^2-300x+17600=0 ?

The solutions to the equation x^2-300x+17600=0 are x=220,x=80

Find the zeros of x^2-300x+17600=0

The zeros of x^2-300x+17600=0 are x=220,x=80

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x^{2} - 300 x + 17600 = 0

x = 220, x = 80

Solution steps

x^{2} - 300 x + 17600 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 300 ) \pm ( - 300 ) ^{2} - 4 \cdot 1 \cdot 17600}{2 \cdot 1}

(- 300)^{2} - 4 \cdot 1 \cdot 17600 = 140

x_{1, 2} = \frac{- ( - 300 ) \pm 140}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 300 ) + 140}{2 \cdot 1}, x_{2} = \frac{- ( - 300 ) - 140}{2 \cdot 1}

x = \frac{- ( - 300 ) + 140}{2 \cdot 1} : 220

x = \frac{- ( - 300 ) - 140}{2 \cdot 1} : 80

The solutions to the quadratic equation are:

x = 220, x = 80

3 x^{2} + 63 x + 12 = 39

x, 2 x^{2} + 2 y^{2} + 2 z^{2} = 8 x - 16 z + 1

y, y^{2} = x^{3} - 5 x + 5

m^{2} + 18 m + 81 = 0

9 = 10 x - x^{2}

What are the solutions to the equation x^2-300x+17600=0 ?
The solutions to the equation x^2-300x+17600=0 are x=220,x=80
Find the zeros of x^2-300x+17600=0
The zeros of x^2-300x+17600=0 are x=220,x=80