What are the solutions to the equation x^2-14x+7=0 ?

The solutions to the equation x^2-14x+7=0 are x=7+sqrt(42),x=7-sqrt(42)

Find the zeros of x^2-14x+7=0

The zeros of x^2-14x+7=0 are x=7+sqrt(42),x=7-sqrt(42)

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x^{2} - 14 x + 7 = 0

x = 7 + 42, x = 7 - 42

Decimal Notation

x = 13.48074 \dots, x = 0.51925 \dots

Solution steps

x^{2} - 14 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 7 = 242

x_{1, 2} = \frac{- ( - 14 ) \pm 2 42}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 2 42}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 2 42}{2 \cdot 1}

x = \frac{- ( - 14 ) + 2 42}{2 \cdot 1} : 7 + 42

x = \frac{- ( - 14 ) - 2 42}{2 \cdot 1} : 7 - 42

The solutions to the quadratic equation are:

x = 7 + 42, x = 7 - 42

\frac{8 d ^{2}}{5} + \frac{3 d ^{2}}{10} = 3 + \frac{2 d ^{2}}{5}

A (x) = x^{2} - 7 x + 2

C = x^{2} - 1200 x + 36400

4 x^{2} - 6 x + 6 = 0

0 = \frac{t ^{2} - t}{3}

What are the solutions to the equation x^2-14x+7=0 ?
The solutions to the equation x^2-14x+7=0 are x=7+sqrt(42),x=7-sqrt(42)
Find the zeros of x^2-14x+7=0
The zeros of x^2-14x+7=0 are x=7+sqrt(42),x=7-sqrt(42)