What are the solutions to the equation 10x^2+20x+6260=0 ?

The solutions to the equation 10x^2+20x+6260=0 are x=-1+25i,x=-1-25i

Find the zeros of 10x^2+20x+6260=0

The zeros of 10x^2+20x+6260=0 are x=-1+25i,x=-1-25i

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10 x^{2} + 20 x + 6260 = 0

x = - 1 + 25 i, x = - 1 - 25 i

Solution steps

10 x^{2} + 20 x + 6260 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 10 \cdot 6260}{2 \cdot 10}

Simplify

2 0^{2} - 4 \cdot 10 \cdot 6260 : 500 i

x_{1, 2} = \frac{- 20 \pm 500 i}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 20 + 500 i}{2 \cdot 10}, x_{2} = \frac{- 20 - 500 i}{2 \cdot 10}

x = \frac{- 20 + 500 i}{2 \cdot 10} : - 1 + 25 i

x = \frac{- 20 - 500 i}{2 \cdot 10} : - 1 - 25 i

The solutions to the quadratic equation are:

x = - 1 + 25 i, x = - 1 - 25 i

11 r^{2} - 5 r - 12 = 7

x^{2} - 14 x + 7 = 0

\frac{8 d ^{2}}{5} + \frac{3 d ^{2}}{10} = 3 + \frac{2 d ^{2}}{5}

A (x) = x^{2} - 7 x + 2

C = x^{2} - 1200 x + 36400

What are the solutions to the equation 10x^2+20x+6260=0 ?
The solutions to the equation 10x^2+20x+6260=0 are x=-1+25i,x=-1-25i
Find the zeros of 10x^2+20x+6260=0
The zeros of 10x^2+20x+6260=0 are x=-1+25i,x=-1-25i