What are the solutions to the equation 11r^2-5r-12=7 ?

The solutions to the equation 11r^2-5r-12=7 are r=(5+sqrt(861))/(22),r=(5-sqrt(861))/(22)

Find the zeros of 11r^2-5r-12=7

The zeros of 11r^2-5r-12=7 are r=(5+sqrt(861))/(22),r=(5-sqrt(861))/(22)

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11 r^{2} - 5 r - 12 = 7

r = \frac{5 + 861}{22}, r = \frac{5 - 861}{22}

Decimal Notation

r = 1.56103 \dots, r = - 1.10649 \dots

Solution steps

11 r^{2} - 5 r - 12 = 7

Move

7

to the left side

11 r^{2} - 5 r - 19 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 11 ( - 19 )}{2 \cdot 11}

(- 5)^{2} - 4 \cdot 11 (- 19) = 861

r_{1, 2} = \frac{- ( - 5 ) \pm 861}{2 \cdot 11}

Separate the solutions

r_{1} = \frac{- ( - 5 ) + 861}{2 \cdot 11}, r_{2} = \frac{- ( - 5 ) - 861}{2 \cdot 11}

r = \frac{- ( - 5 ) + 861}{2 \cdot 11} : \frac{5 + 861}{22}

r = \frac{- ( - 5 ) - 861}{2 \cdot 11} : \frac{5 - 861}{22}

The solutions to the quadratic equation are:

r = \frac{5 + 861}{22}, r = \frac{5 - 861}{22}

x^{2} - 14 x + 7 = 0

\frac{8 d ^{2}}{5} + \frac{3 d ^{2}}{10} = 3 + \frac{2 d ^{2}}{5}

A (x) = x^{2} - 7 x + 2

C = x^{2} - 1200 x + 36400

4 x^{2} - 6 x + 6 = 0

What are the solutions to the equation 11r^2-5r-12=7 ?
The solutions to the equation 11r^2-5r-12=7 are r=(5+sqrt(861))/(22),r=(5-sqrt(861))/(22)
Find the zeros of 11r^2-5r-12=7
The zeros of 11r^2-5r-12=7 are r=(5+sqrt(861))/(22),r=(5-sqrt(861))/(22)