What are the solutions to the equation x^2-2x+1=-x^2+5 ?

The solutions to the equation x^2-2x+1=-x^2+5 are x=2,x=-1

Find the zeros of x^2-2x+1=-x^2+5

The zeros of x^2-2x+1=-x^2+5 are x=2,x=-1

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x^{2} - 2 x + 1 = - x^{2} + 5

x = 2, x = - 1

Solution steps

x^{2} - 2 x + 1 = - x^{2} + 5

Move

5

to the left side

x^{2} - 2 x - 4 = - x^{2}

Move

x^{2}

to the left side

2 x^{2} - 2 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 2 ( - 4 )}{2 \cdot 2}

(- 2)^{2} - 4 \cdot 2 (- 4) = 6

x_{1, 2} = \frac{- ( - 2 ) \pm 6}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 6}{2 \cdot 2}, x_{2} = \frac{- ( - 2 ) - 6}{2 \cdot 2}

x = \frac{- ( - 2 ) + 6}{2 \cdot 2} : 2

x = \frac{- ( - 2 ) - 6}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

x = 2, x = - 1

x^{2} + 18 x + 81 = 0

x^{2} - 30 x + 224 = 0

λ^{2} + 14 λ + 49 = 0

4 y^{2} - 21 y - 18 = 0

x^{2} + 26 x + c

What are the solutions to the equation x^2-2x+1=-x^2+5 ?
The solutions to the equation x^2-2x+1=-x^2+5 are x=2,x=-1
Find the zeros of x^2-2x+1=-x^2+5
The zeros of x^2-2x+1=-x^2+5 are x=2,x=-1