What are the solutions to the equation -8x-16=x^2 ?

The solutions to the equation -8x-16=x^2 are x=-4

Find the zeros of -8x-16=x^2

The zeros of -8x-16=x^2 are x=-4

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- 8 x - 16 = x^{2}

x = - 4

Solution steps

- 8 x - 16 = x^{2}

Switch sides

x^{2} = - 8 x - 16

Move

16

to the left side

x^{2} + 16 = - 8 x

Move

8 x

to the left side

x^{2} + 16 + 8 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 8 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 16 = 0

x_{1, 2} = \frac{- 8 \pm 0}{2 \cdot 1}

x = \frac{- 8}{2 \cdot 1}

\frac{- 8}{2 \cdot 1} = - 4

x = - 4

The solution to the quadratic equation is:

x = - 4

9 x^{2} - 9 x + 11 = 0

- x (- 2 - x) - 2 = 0

(x + a)^{2} - b^{2} = 0

2 x^{2} - 3 x + 1 = 0

\frac{1}{8} x^{2} - \frac{3}{4} x + 1 = 0

What are the solutions to the equation -8x-16=x^2 ?
The solutions to the equation -8x-16=x^2 are x=-4
Find the zeros of -8x-16=x^2
The zeros of -8x-16=x^2 are x=-4