What are the solutions to the equation -x(-2-x)-2=0 ?

The solutions to the equation -x(-2-x)-2=0 are x=-1+sqrt(3),x=-1-sqrt(3)

Find the zeros of -x(-2-x)-2=0

The zeros of -x(-2-x)-2=0 are x=-1+sqrt(3),x=-1-sqrt(3)

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- x (- 2 - x) - 2 = 0

x = - 1 + 3, x = - 1 - 3

Decimal Notation

x = 0.73205 \dots, x = - 2.73205 \dots

Solution steps

- x (- 2 - x) - 2 = 0

Expand

- x (- 2 - x) - 2 : 2 x + x^{2} - 2

2 x + x^{2} - 2 = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 2 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 2) = 23

x_{1, 2} = \frac{- 2 \pm 2 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 3}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 3}{2 \cdot 1}

x = \frac{- 2 + 2 3}{2 \cdot 1} : - 1 + 3

x = \frac{- 2 - 2 3}{2 \cdot 1} : - 1 - 3

The solutions to the quadratic equation are:

x = - 1 + 3, x = - 1 - 3

(x + a)^{2} - b^{2} = 0

2 x^{2} - 3 x + 1 = 0

\frac{1}{8} x^{2} - \frac{3}{4} x + 1 = 0

0.0102 s^{2} + 0.5151 s + 1.255 = 0

3 x (x - 2) = 8 x^{2} - 7 x

What are the solutions to the equation -x(-2-x)-2=0 ?
The solutions to the equation -x(-2-x)-2=0 are x=-1+sqrt(3),x=-1-sqrt(3)
Find the zeros of -x(-2-x)-2=0
The zeros of -x(-2-x)-2=0 are x=-1+sqrt(3),x=-1-sqrt(3)