What are the solutions to the equation x^2-17x+18=0 ?

The solutions to the equation x^2-17x+18=0 are x=(17+sqrt(217))/2 ,x=(17-sqrt(217))/2

Find the zeros of x^2-17x+18=0

The zeros of x^2-17x+18=0 are x=(17+sqrt(217))/2 ,x=(17-sqrt(217))/2

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x^{2} - 17 x + 18 = 0

x = \frac{17 + 217}{2}, x = \frac{17 - 217}{2}

Decimal Notation

x = 15.86545 \dots, x = 1.13454 \dots

Solution steps

x^{2} - 17 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

(- 17)^{2} - 4 \cdot 1 \cdot 18 = 217

x_{1, 2} = \frac{- ( - 17 ) \pm 217}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 17 ) + 217}{2 \cdot 1}, x_{2} = \frac{- ( - 17 ) - 217}{2 \cdot 1}

x = \frac{- ( - 17 ) + 217}{2 \cdot 1} : \frac{17 + 217}{2}

x = \frac{- ( - 17 ) - 217}{2 \cdot 1} : \frac{17 - 217}{2}

The solutions to the quadratic equation are:

x = \frac{17 + 217}{2}, x = \frac{17 - 217}{2}

y^{2} = - 2, 7 + 36 + 8 = 17

139.39 = - 4.9 t^{2} + 73.92 t

2^{3} b^{2} = 2^{7}

4 x^{2} - 16 x + 16 = 4 x

x^{2} + 6 - 5 x = 0

What are the solutions to the equation x^2-17x+18=0 ?
The solutions to the equation x^2-17x+18=0 are x=(17+sqrt(217))/2 ,x=(17-sqrt(217))/2
Find the zeros of x^2-17x+18=0
The zeros of x^2-17x+18=0 are x=(17+sqrt(217))/2 ,x=(17-sqrt(217))/2