What are the solutions to the equation 6a^2+5a-4=2 ?

The solutions to the equation 6a^2+5a-4=2 are a= 2/3 ,a=-3/2

Find the zeros of 6a^2+5a-4=2

The zeros of 6a^2+5a-4=2 are a= 2/3 ,a=-3/2

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6 a^{2} + 5 a - 4 = 2

a = \frac{2}{3}, a = - \frac{3}{2}

Decimal Notation

a = 0.66666 \dots, a = - 1.5

Solution steps

6 a^{2} + 5 a - 4 = 2

Move

2

to the left side

6 a^{2} + 5 a - 6 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 6 ( - 6 )}{2 \cdot 6}

5^{2} - 4 \cdot 6 (- 6) = 13

a_{1, 2} = \frac{- 5 \pm 13}{2 \cdot 6}

Separate the solutions

a_{1} = \frac{- 5 + 13}{2 \cdot 6}, a_{2} = \frac{- 5 - 13}{2 \cdot 6}

a = \frac{- 5 + 13}{2 \cdot 6} : \frac{2}{3}

a = \frac{- 5 - 13}{2 \cdot 6} : - \frac{3}{2}

The solutions to the quadratic equation are:

a = \frac{2}{3}, a = - \frac{3}{2}

6 + x - x^{2} = x^{2}

(3 x + 4)^{2} = 8

m (m + 2) = - 3 - 2 m

4 x^{2} - 24 x + 42

4 + (x - 2)^{2} = x (4 - x)

What are the solutions to the equation 6a^2+5a-4=2 ?
The solutions to the equation 6a^2+5a-4=2 are a= 2/3 ,a=-3/2
Find the zeros of 6a^2+5a-4=2
The zeros of 6a^2+5a-4=2 are a= 2/3 ,a=-3/2