What are the solutions to the equation solvefor a,70a^2-149ab+70b^2=0 ?

The solutions to the equation solvefor a,70a^2-149ab+70b^2=0 are a=(10b)/7 ,a=(7b)/(10)

Find the zeros of solvefor a,70a^2-149ab+70b^2=0

The zeros of solvefor a,70a^2-149ab+70b^2=0 are a=(10b)/7 ,a=(7b)/(10)

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solve for

a, 70 a^{2} - 149 ab + 70 b^{2} = 0

a = \frac{10 b}{7}, a = \frac{7 b}{10}

Solution steps

70 a^{2} - 149 ab + 70 b^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

70 a^{2} - 149 ba + 70 b^{2} = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 149 b ) \pm ( - 149 b ) ^{2} - 4 \cdot 70 \cdot 70 b ^{2}}{2 \cdot 70}

Simplify

(- 149 b)^{2} - 4 \cdot 70 \cdot 70 b^{2} : 51 b

a_{1, 2} = \frac{- ( - 149 b ) \pm 51 b}{2 \cdot 70}

Separate the solutions

a_{1} = \frac{- ( - 149 b ) + 51 b}{2 \cdot 70}, a_{2} = \frac{- ( - 149 b ) - 51 b}{2 \cdot 70}

a = \frac{- ( - 149 b ) + 51 b}{2 \cdot 70} : \frac{10 b}{7}

a = \frac{- ( - 149 b ) - 51 b}{2 \cdot 70} : \frac{7 b}{10}

The solutions to the quadratic equation are:

a = \frac{10 b}{7}, a = \frac{7 b}{10}

8 x^{2} - 55 x + 42 = 0

t^{2} + 2 t + 3 = 0

3 y^{2} - 17 y + 10 = 0

t^{2} + 2 t + 2 = 0

2 x^{2} - 6 = - 168

What are the solutions to the equation solvefor a,70a^2-149ab+70b^2=0 ?
The solutions to the equation solvefor a,70a^2-149ab+70b^2=0 are a=(10b)/7 ,a=(7b)/(10)
Find the zeros of solvefor a,70a^2-149ab+70b^2=0
The zeros of solvefor a,70a^2-149ab+70b^2=0 are a=(10b)/7 ,a=(7b)/(10)