What are the solutions to the equation 7d^2+8d-3=0 ?

The solutions to the equation 7d^2+8d-3=0 are d=(-4+sqrt(37))/7 ,d=-(4+sqrt(37))/7

Find the zeros of 7d^2+8d-3=0

The zeros of 7d^2+8d-3=0 are d=(-4+sqrt(37))/7 ,d=-(4+sqrt(37))/7

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7 d^{2} + 8 d - 3 = 0

d = \frac{- 4 + 37}{7}, d = - \frac{4 + 37}{7}

Decimal Notation

d = 0.29753 \dots, d = - 1.44039 \dots

Solution steps

7 d^{2} + 8 d - 3 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 7 ( - 3 )}{2 \cdot 7}

8^{2} - 4 \cdot 7 (- 3) = 237

d_{1, 2} = \frac{- 8 \pm 2 37}{2 \cdot 7}

Separate the solutions

d_{1} = \frac{- 8 + 2 37}{2 \cdot 7}, d_{2} = \frac{- 8 - 2 37}{2 \cdot 7}

d = \frac{- 8 + 2 37}{2 \cdot 7} : \frac{- 4 + 37}{7}

d = \frac{- 8 - 2 37}{2 \cdot 7} : - \frac{4 + 37}{7}

The solutions to the quadratic equation are:

d = \frac{- 4 + 37}{7}, d = - \frac{4 + 37}{7}

x^{2} + 2 x \cdot 9 = 2 x + 2 \cdot 40

0 = x^{2} + 12 x + 37

x^{2} - x - 35 = x + 1

(2 x + 1) (x - 6) = 0

- 6 x^{2} - 36 x + 42 = 0

What are the solutions to the equation 7d^2+8d-3=0 ?
The solutions to the equation 7d^2+8d-3=0 are d=(-4+sqrt(37))/7 ,d=-(4+sqrt(37))/7
Find the zeros of 7d^2+8d-3=0
The zeros of 7d^2+8d-3=0 are d=(-4+sqrt(37))/7 ,d=-(4+sqrt(37))/7