What are the solutions to the equation solvefor a,a^2-ab+b^2=0 ?

The solutions to the equation solvefor a,a^2-ab+b^2=0 are a= b/2+i(sqrt(3)b)/2 ,a= b/2-i(sqrt(3)b)/2

Find the zeros of solvefor a,a^2-ab+b^2=0

The zeros of solvefor a,a^2-ab+b^2=0 are a= b/2+i(sqrt(3)b)/2 ,a= b/2-i(sqrt(3)b)/2

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solve for

a, a^{2} - ab + b^{2} = 0

a = \frac{b}{2} + i \frac{3 b}{2}, a = \frac{b}{2} - i \frac{3 b}{2}

Solution steps

a^{2} - ab + b^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

a^{2} - ba + b^{2} = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - b ) \pm ( - b ) ^{2} - 4 \cdot 1 \cdot b ^{2}}{2 \cdot 1}

Simplify

(- b)^{2} - 4 \cdot 1 \cdot b^{2} : 3 ib

a_{1, 2} = \frac{- ( - b ) \pm 3 ib}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - b ) + 3 ib}{2 \cdot 1}, a_{2} = \frac{- ( - b ) - 3 ib}{2 \cdot 1}

a = \frac{- ( - b ) + 3 ib}{2 \cdot 1} : \frac{b}{2} + i \frac{3 b}{2}

a = \frac{- ( - b ) - 3 ib}{2 \cdot 1} : \frac{b}{2} - i \frac{3 b}{2}

The solutions to the quadratic equation are:

a = \frac{b}{2} + i \frac{3 b}{2}, a = \frac{b}{2} - i \frac{3 b}{2}

s^{2} + s + 2 + k = 0

\frac{5}{16} x^{2} - x - 1 = 0

6 a^{2} - 9 a + 15 = 0

x^{2} + 2 x = 9 x - 6

2 x^{2} + 4 x - 96 = 0

What are the solutions to the equation solvefor a,a^2-ab+b^2=0 ?
The solutions to the equation solvefor a,a^2-ab+b^2=0 are a= b/2+i(sqrt(3)b)/2 ,a= b/2-i(sqrt(3)b)/2
Find the zeros of solvefor a,a^2-ab+b^2=0
The zeros of solvefor a,a^2-ab+b^2=0 are a= b/2+i(sqrt(3)b)/2 ,a= b/2-i(sqrt(3)b)/2