What are the solutions to the equation x^2+2x=9x-6 ?

The solutions to the equation x^2+2x=9x-6 are x=6,x=1

Find the zeros of x^2+2x=9x-6

The zeros of x^2+2x=9x-6 are x=6,x=1

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x^{2} + 2 x = 9 x - 6

x = 6, x = 1

Solution steps

x^{2} + 2 x = 9 x - 6

Move

6

to the left side

x^{2} + 2 x + 6 = 9 x

Move

9 x

to the left side

x^{2} - 7 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 6 = 5

x_{1, 2} = \frac{- ( - 7 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 5}{2 \cdot 1}

x = \frac{- ( - 7 ) + 5}{2 \cdot 1} : 6

x = \frac{- ( - 7 ) - 5}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 6, x = 1

2 x^{2} + 4 x - 96 = 0

x, z = 4 x^{2} + y^{2} + 4

x^{2} - 8 = 41

x^{2} - 10 x = - 29

x^{2} + 8 x - 24 = 3 x

What are the solutions to the equation x^2+2x=9x-6 ?
The solutions to the equation x^2+2x=9x-6 are x=6,x=1
Find the zeros of x^2+2x=9x-6
The zeros of x^2+2x=9x-6 are x=6,x=1