What are the solutions to the equation s^2+s+2+k=0 ?

The solutions to the equation s^2+s+2+k=0 are s=(-1+sqrt(-4k-7))/2 ,s=(-1-sqrt(-4k-7))/2

Find the zeros of s^2+s+2+k=0

The zeros of s^2+s+2+k=0 are s=(-1+sqrt(-4k-7))/2 ,s=(-1-sqrt(-4k-7))/2

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s^{2} + s + 2 + k = 0

s = \frac{- 1 + - 4 k - 7}{2}, s = \frac{- 1 - - 4 k - 7}{2}

Solution steps

s^{2} + s + 2 + k = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( 2 + k )}{2 \cdot 1}

Simplify

1^{2} - 4 \cdot 1 \cdot (2 + k) : - 4 k - 7

s_{1, 2} = \frac{- 1 \pm - 4 k - 7}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 1 + - 4 k - 7}{2 \cdot 1}, s_{2} = \frac{- 1 - - 4 k - 7}{2 \cdot 1}

s = \frac{- 1 + - 4 k - 7}{2 \cdot 1} : \frac{- 1 + - 4 k - 7}{2}

s = \frac{- 1 - - 4 k - 7}{2 \cdot 1} : \frac{- 1 - - 4 k - 7}{2}

The solutions to the quadratic equation are:

s = \frac{- 1 + - 4 k - 7}{2}, s = \frac{- 1 - - 4 k - 7}{2}

\frac{5}{16} x^{2} - x - 1 = 0

6 a^{2} - 9 a + 15 = 0

x^{2} + 2 x = 9 x - 6

2 x^{2} + 4 x - 96 = 0

x, z = 4 x^{2} + y^{2} + 4

What are the solutions to the equation s^2+s+2+k=0 ?
The solutions to the equation s^2+s+2+k=0 are s=(-1+sqrt(-4k-7))/2 ,s=(-1-sqrt(-4k-7))/2
Find the zeros of s^2+s+2+k=0
The zeros of s^2+s+2+k=0 are s=(-1+sqrt(-4k-7))/2 ,s=(-1-sqrt(-4k-7))/2