What are the solutions to the equation 6a^2-9a+15=0 ?

The solutions to the equation 6a^2-9a+15=0 are a= 3/4+i(sqrt(31))/4 ,a= 3/4-i(sqrt(31))/4

Find the zeros of 6a^2-9a+15=0

The zeros of 6a^2-9a+15=0 are a= 3/4+i(sqrt(31))/4 ,a= 3/4-i(sqrt(31))/4

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6 a^{2} - 9 a + 15 = 0

a = \frac{3}{4} + i \frac{31}{4}, a = \frac{3}{4} - i \frac{31}{4}

Solution steps

6 a^{2} - 9 a + 15 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 6 \cdot 15}{2 \cdot 6}

Simplify

(- 9)^{2} - 4 \cdot 6 \cdot 15 : 331 i

a_{1, 2} = \frac{- ( - 9 ) \pm 3 31 i}{2 \cdot 6}

Separate the solutions

a_{1} = \frac{- ( - 9 ) + 3 31 i}{2 \cdot 6}, a_{2} = \frac{- ( - 9 ) - 3 31 i}{2 \cdot 6}

a = \frac{- ( - 9 ) + 3 31 i}{2 \cdot 6} : \frac{3}{4} + i \frac{31}{4}

a = \frac{- ( - 9 ) - 3 31 i}{2 \cdot 6} : \frac{3}{4} - i \frac{31}{4}

The solutions to the quadratic equation are:

a = \frac{3}{4} + i \frac{31}{4}, a = \frac{3}{4} - i \frac{31}{4}

x^{2} + 2 x = 9 x - 6

2 x^{2} + 4 x - 96 = 0

x, z = 4 x^{2} + y^{2} + 4

x^{2} - 8 = 41

x^{2} - 10 x = - 29

What are the solutions to the equation 6a^2-9a+15=0 ?
The solutions to the equation 6a^2-9a+15=0 are a= 3/4+i(sqrt(31))/4 ,a= 3/4-i(sqrt(31))/4
Find the zeros of 6a^2-9a+15=0
The zeros of 6a^2-9a+15=0 are a= 3/4+i(sqrt(31))/4 ,a= 3/4-i(sqrt(31))/4